山东省枣庄市滕州市2023-2024学年高三上学期期中考试 数学答案

2023-11-15 · U1 上传 · 6页 · 670.6 K

2024届高三定时训练3(2−,0]2369ea=4Axx={|57}B={x|x3x5}ABxx={|57}a22aa−1+1A=ABa2211aa−+A2a−13a+15a2a2a=2a4{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}aaa|2a4fxxxa()(3)()=−−a3fx()0(,3)aa=3fx()0a3fx()0(3,)afxxxa()(3)()=−−9x+[4,)fx()9−ax+x−3999x+=x−3++32(x−3)+3=9x−3x−3x−39x−=3x=6x−3a9a{|9}aaf(x)=3sin2x+cos2x+131=++2(sin2cos2xx)122π=2sin(2x+)+16{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}ππ3π2kxkπ+++22πkZ262π2πkxkπ++π63π2π[kkπ++,π]kZ63π1fA()=2,sin(2)A+=62π5ππA(0,π)2A+=A=663a=23a2=b2+c2−2bccosAb22+c−bc=12bcbcbc=+−−2212212bc12bc==2313SbcAbc==sin3324△ABC33fx()Rx0fxx()e=2xx0时−x0f(xfxxx)(=−)[e−]e=−(−=)−22−−xx−xx2e,−x0fx()=2xxxe,0f(ax22−31)x−+ax−31x−−f(5−ax)+ax−5{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}xRfaxxaxxfaxax(31)3122−−+−−−+−(5)5xRh()()x=+fxxhx()Raxxax2−−−315xRaxax2−++(3)40a0a0(36+−aa)21019aa(1,9)22n=122aa11=+a1=22n222aSannnn=+,2可得2()()2SSSSSnnnnnn−=−+−−1122SSnnn−=−12222222222Sn=S1+()()()S2−S1+S3−S2++Sn−Sn+1=n+n2Sn=n+n=n(n+1)an=Sn−Sn−1=n(n+1)−(n−1)n............................................5分a1=2{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}annnnn=+−−(1)(1)annnnn+1=++−+(1)(2)(1)212nn+故aa−=−nn+1nnnn++++−21121(11)2(2)nnnnnn+++−−++=(2)(11)nnnn++++−2(1)21222nnnnn++−−+−22=(2)(11)nnnn++++−2(11)22+−−+nnn22=...............................................8分(2)(11)nnnn++++−(11)212(2+−=+−nnnnnnn2222222+=+)112+−+nnn22aann+1−0anamn−22am1−22m21fx()(0,+)f()x=+mxm0fx()01m0x−(0,)fx()0m{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}1x−(,+)fx()0fx()m11x=−ln()−=0mmm=−1xfx(g)(x)ln1x+m+−1ex(0,)+xln1x+xx2ex+ln()ex=−x()x=xx21qxxx()eln=+2xq(x)=(x2+2x)ex+0x1qx()q()0q(1)022x0x0xx00eln0+=xx00lnx0−lnxx00elne=−=−x0xh(x)=xehxhx()(ln)00=−xx00=−ln()x(0,)x0(,x)0+x0ln11xx00+−1(xx)(=−=+=)0e1xxx000m(−,0]{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}

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